'A buffer solution is formed by adding 0.500 mol of sodium acetate and 0.500 mol of acetic acid to 1.00 L HzO. What is the pH of the solution at equilibrium? (Ka 1.80 * 10-5)'
Added by Shawn H.
Step 1
Given: - Moles of acetic acid (CH3COOH) = 0.500 mol - Moles of sodium acetate (CH3COONa) = 0.500 mol - Volume of solution = 1.00 L Concentration of acetic acid = 0.500 mol / 1.00 L = 0.500 M Concentration of sodium acetate = 0.500 mol / 1.00 L = 0.500 M Show more…
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