Question

A buffer solution of pH = 5.30 can be prepared by dissolving acetic acid (CH3COOH) and sodium acetate (NaCH3COO) in water. How many moles of sodium acetate must be added to 1.00 L of 0.250 M acetic acid to prepare the buffer? Ka = 1.76 x 10-5

Name: a buffer solution of ph 530 can be prepared by dissolving acetic acid ch3cooh and sodium acetate nach3coo in water how many moles of sodium acetate must be added to 100 l of 0250 m acetic ac 55723
Uploaded: 2022-09-21T10:29:29-08:00
Duration: 2 min 23 s
Channel: Adi S
Description: a buffer solution of ph 530 can be prepared by dissolving acetic acid ch3cooh and sodium acetate nach3coo in water how many moles of sodium acetate must be added to 100 l of 0250 m acetic ac 55723

          A buffer solution of pH = 5.30 can be prepared by dissolving
acetic acid (CH3COOH) and sodium
acetate (NaCH3COO) in water.
How many moles of sodium acetate must be added to 1.00 L of
0.250 M acetic acid to prepare the
buffer?  Ka = 1.76 x
10-5

Added by Alexander R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/21/2022

Step 1

Given: pH = 5.30 Ka = 1.76 x 10^-5 [CH3COOH] = 0.250 M Using the Henderson-Hasselbalch equation: pH = pKa + log([salt]/[acid]) 5.30 = 4.75 + log([salt]/0.250) 0.55 = log([salt]/0.250) [salt]/0.250 = 10^0.55 [salt] = 0.250 * 10^0.55 [salt] = 0.250 * 3.48 [salt] = Show more…

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A buffer solution of pH = 5.30 can be prepared by dissolving acetic acid (CH3COOH) and sodium acetate (NaCH3COO) in water. How many moles of sodium acetate must be added to 1.00 L of 0.250 M acetic acid to prepare the buffer? Ka = 1.76 x 10-5