A bullet is fired at an angle of 60 degrees with an initial velocity of 200.0 m/s. How long is the bullet in the air? What is the maximum height reached by the bullet?
Added by Scott P.
Step 1
0*cos(60°) = 200.0*(0.5) = 100.0 m/s; v0y = 200.0*sin(60°) = 200.0*(√3/2) = 100.0√3 ≈ 173.205 m/s. Show more…
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