A bullet of mass 8.48 g that is moving at a speed of 438 m/s embeds itself into a tree, penetrating 22.3 cm into the wood. What is the magnitude of the average force, in N, exerted by the tree on the bullet?
Added by Anna P.
Step 1
First, we need to find the initial kinetic energy of the bullet. The formula for kinetic energy is: KE = (1/2)mv^2 where m is the mass of the bullet and v is its velocity. Show more…
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