A bullet of mass m = 200 g is fired at speed v0 = 210 m/s into a wooden block of mass M = 4.0 Kg. The bullet instantaneously comes to rest in the block. The block with the embedded bullet slides along a horizontal frictionless surface. What is the velocity of the block-bullet system after the collision?
Added by David C.
Step 1
First, let's calculate the momentum of the bullet before the collision. The momentum of an object is given by the product of its mass and velocity. So, the momentum of the bullet before the collision is: Momentum of bullet before collision = mass of bullet * Show more…
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