A bullet shot underwater will experience "viscous drag" and follow this velocity equation:
vx(t) = vi * e^(-bt)
where vi = 285 m/s and b = 0.35 s^-1.
The bullet has an initial position xi = 32.3 m at ti = 0 s.
What is the location of the bullet at time t = 0.54 seconds?
What is the maximum position of the bullet (if you wait a long time, what will its position be)?
What is the x component of the acceleration of the bullet 0.5 seconds after the bullet is fired?