A bus driver heads south with a steady speed of v1 220 ms...

A bus driver heads south with a steady speed of v1 = 22.0 m/s for t1 = 3.00 min, then makes a right turn and travels at v2 = 25.0 m/s for t2 = 2.20 min, and then drives northwest at v3 = 30.0 m/s for t3 = 1.00 min. For this 6.20-min trip, calculate the following. Assume +x is in the eastward direction. (a) Total vector displacement (Enter the magnitude in m and the direction in degrees south of west.) Magnitude: m Direction: ° south of west (b) Average speed (in m/s) m/s (c) Average velocity (Enter the magnitude in m/s and the direction in degrees south of west.) Magnitude: m/s Direction: ° south of west

Transcript

00:01 Now the first question asked for the vector displacement.

00:03 So first let us determine the distance travel per each time interval stated.

00:12 So for the first distance, you know that the formula for velocity is displacement over the time.

00:22 Then for this displacement, we have the product of the velocity and the time interval.

00:29 We're given a velocity of 22 meter per second.

00:33 For three minutes.

00:36 So that is 180 seconds and we can find that the displacement here is 3 ,160 meters next for the second rule we are given and staining velocity of 25 meter per second for a time of 2 .2 minutes so that is 132 seconds and this is equals to 3 ,300 and 3 .303 and for the last route, the instantaneous velocity is 30 meter per second, for 60 seconds, change the facility to be one minute.

01:29 This is 1 ,800 meters.

01:33 Now we're given the direction of the first route as towards south, the second route as north -west, and the last route.

01:43 The second route is since he makes a right turn from south, then it is the second route.

01:56 Towards west.

01:59 Then the last route was stated that he goes north -west.

02:10 So the vector of displacement is given by this equation.

02:20 For r sub -x here is the sum of the horizontal components and r -sub -wise is some of the vertical component.

02:27 So let's start with the horizontal component.

02:30 So for the first route, there's no horizontal component since it was going south.

02:38 For the second we have 3 ,000 meters but it is negative since it is towards west.

02:52 And for the last route, it is also negative since we have a west component.

03:02 And if the stated the direction is north -west, meaning the angle is 45 degrees...

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