00:01
So everyone so got up to the question uh we need to be find out over here the amount of work done against what again the atmospheric pressure and pressure is given over here the one atmosphere when the 500 gram of zinc is going to be dissolved in the excess acid of 30 degree shelters so we are going to be writing up the given equation would be like this way zin solid to h plus of equius it is going to give us z n 2 plus equius plus h2 in the caches so since i would like to write it over here because worked on is how much that amount we need to calculate i would like to write it over here the given that is a what mass of zinc is a 500 gram and molar mass of zinc is equal to how much 65 .4 gram divided by mole therefore moles of zinc is how much it could be we need to do the divide 500 gram divided by 65 .4 gram divided by moles so we are getting over here the mole of zinc therefore all of zinc is equal to 7 .65 mole of zinc which given this much more of h2 which gives i would like to write this much will gives 7 .65 moles of h2 here we are going to be considering that n as then what h2 we are going to be considering also that more sporic pressure i would like to write it over here also atmospheric pressure, okay, i can write it, atmospheric pressure as an p, we are going to be writing that is one atmosphere that i have already told in the very beginning and temperature is given over here.
02:38
Temperature is equal to 30 degree celsius.
02:41
We need to calculate in the calvin.
02:43
So i would like to write it over here 303 kelvin.
02:45
Calvin, now we are using here the equation that is pv is equal to what n rt where n we are have already taken here.
02:55
That is what nh2o right? so i would like to write it over here in the form of v and rt divided by p.
03:04
So i'm going to be putting all the values over here.
03:07
And after putting the values, what we are getting, we are getting like this way.
03:11
7 .65 mole multiplied by 0 .0 821 litre atmosphere k inverse mole inverse divided by it is okay it's going to become over here 303 calvin 1 atmosphere so i would like to write it over here therefore volume of h2 is produce is equal to v is equal to 190 .18 liter so this is a required one another we are going to be moving up further begin right now the main we need to be find out that part is going to become work w is equal to what minus p multiplied by delta v so w that is going to be writing minus one atmosphere.
04:17
You multiply just now we have calculated delta v...