Question

A) Calculate the energy of a photon of radiation whose wavelength is 427 nm. B) What wavelength of radiation has photons of energy 6.11×10^(-19) J?

          A) Calculate the energy of a photon of radiation whose wavelength is 427 nm.
B) What wavelength of radiation has photons of energy 6.11×10^(-19) J?
        

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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A) Calculate the energy of a photon of radiation whose wavelength is 427 nm. B) What wavelength of radiation has photons of energy 6.11×10^(-19) J?
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Transcript

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00:01 We have two parts here and here in both of the parts the concept involved is plank theory of electromagnetic radiation so this means that the theory says that the electromagnetic radiation travels in the form of small energy packets and these small energy packets are called photons okay so now the energy of radiation that is further directly proportional to the frequency of radiation.
00:33 So we can say that energy e that is directly proportional to frequency new.
00:41 So removing this proportionality sign, so e is equals to h new.
00:45 So h is the plank constant.
00:47 Okay.
00:48 So now further since new is equals to c divided by lambda.
00:55 So we have frequency and we have speed of light and we have wavelength.
01:02 So we can write e is equals to hc divided by lambda.
01:09 So now we have a part and this says that we have to calculate the energy for single photon.
01:20 Okay.
01:21 So here n is the positive integral value that represents the value for photon.
01:29 N is the number of photons having positive integral value now we have here n is equals to 1 we have to calculate for one photon only so now e is equal to 1 multiplied by plank constant 6 .626 multiplied 10 raised power minus 34 jule second multiplied by we have speed of light that is 3 multiplying 10 rift to power 8 meter second inverse divided by we have wavelength that is 427 nanometer...
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