A calculate the molarity of a solution that contains 00345...

(a) Calculate the molarity of a solution that contains 0.0345 mol NH4Cl in exactly 400 mL of solution. (b) How many moles of HNO3 are present in 35.0 mL of a 2.20 M solution of nitric acid? (c) How many milliliters of 1.50 M KOH solution are needed to provide 0.125 mol of KOH?

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Transcript

00:01 So to solve for this, i'll let first equation.

00:06 Malarity, which are presented by capital letter m, that's like we went to the mole of salute, divided by the volume of the solution, which should be in liters.

00:17 Okay, so that's malaria.

00:19 So using that equation, we are to calculate the similarity of the given solution, and we'll be given to the number of moles, 2 .0, 3, 4, 5, this is, all divided by the volume.

00:30 So we have the volume in an hour.

00:32 So 400m.

00:33 We convert this to liters.

00:35 The conversion factor is that 1 ,000m is 1 liter.

00:40 So we should be able to cancel this now.

00:42 And there are many units.

00:43 One formality, moles per liter.

00:46 So we have 0 .0863.

00:50 This is most per liter.

00:53 That's similarity.

00:55 Okay.

00:56 That's for a and then for b.