00:01
Hello, we have the first answer question a.
00:02
Here we have to calculate number of electrons in a neutral silver wire with a mass of 9 grams.
00:15
So first to calculate this number of elections, let's calculate the formula.
00:20
Let's determine the formula, that is number of moles of elections and times avagadro number.
00:33
So here a number of most of elections is mass of silver divided by its smaller mass times 47 and times avagadra number.
00:54
Let's complete this calculation.
00:59
So here this ratio is 9 grams over 107 .87 gram per month.
01:09
Now let's complete this calculation.
01:14
2 .4 times 10 power by 24 electrons.
01:23
Now once it's solved, we can move on to the next question, which is question b.
01:31
And in question b we have to determine how many elections we need to add for every million present...