A camera on the left edge of a circular track of radius D=4m tracks a particle as it travels around the
circle. The polar equation of the path is given above.
At the moment shown, the camera angle is heta =30deg , and the camera is rotating at heta ^(˙)=0.5ra(d)/(s), which is
accelerating at a rate heta ^(¨)=-0.1ra(d)/(s^(2)). What is the velocity, acceleration, and rate of change of speed of
the particle at that instant?
v=,(m)/(s)
a=,(m)/(s^(2))
v^(˙)=,(m)/(s^(2))
r=Dcos0
A camera on the left edge of a circular track of radius D=4 m tracks a particle as it travels around the circle. The polar equation of the path is given above.
At the moment shown,the camera angle is =30,and the camera is rotating at =0.5 rad/s,which is accelerating at a rate = --0.1 rad/s2. What is the velocity, acceleration, and rate of change of speed of the particle at that instant?
m/s
1
m/s2
v=
m/s2