Question

A cancer cell has a maximal specific growth rate of m = -0.04 h. The goal is to grow a lot of cancer cells over 24 hours because, after growing them, you plan to investigate the response of different samples of cells to different drugs. a: Initially, there is Xo = 0.2 g dry weight/liter of cells present. Using the growth expression X = Xo * exp(mt), calculate the cell mass after 24 hours of incubation. b: The yield on glucose is Y = 0.3 g cell dry weight/g glucose. Using the expression (X - Xo)/Y = S for the consumed glucose of mass/liter, calculate S. c: Will 2 g glucose/liter be sufficient to support growth for 24 hours?

          A cancer cell has a maximal specific growth rate of m = -0.04 h. The goal is to grow a lot of cancer cells over 24 hours because, after growing them, you plan to investigate the response of different samples of cells to different drugs.

a: Initially, there is Xo = 0.2 g dry weight/liter of cells present. Using the growth expression X = Xo * exp(mt), calculate the cell mass after 24 hours of incubation.

b: The yield on glucose is Y = 0.3 g cell dry weight/g glucose. Using the expression (X - Xo)/Y = S for the consumed glucose of mass/liter, calculate S.

c: Will 2 g glucose/liter be sufficient to support growth for 24 hours?

a cancer cell has a maximal specific growth rate of m 004 hthe goal is to grow a lot of cancer cells over 24 hoursbecause after growing themyou plan to investigate the response of different 84246

Added by Jeremy S.

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