00:03
So in this question let us assume d equal to 20 mm and here d is our thickness and e is our elastic constant for the bolt is 207 kilo newton per mm square.
00:19
Same for the cast iron, cast iron is 100 kilo newton per mm square and same goes for the zinc.
00:31
It is 90 kilo newton per mm square.
00:36
Now first what will we do? we will find the stiffness of bolt.
00:40
So the stiffness of bolt is given by the formula pi by 4 multiplied by d square multiplied by e and here we put the value that is pi by 4 multiplied by 20 the whole square.
00:57
That we have assumed earlier and the e value for the bolt is 207 and 40.
01:04
Here the thickness is 2 times of d.
01:07
Therefore 2 into 20 equal to 40.
01:10
After solving it we get the value of our stiffness constant kb that is 1625 .774 kilo newton per mm.
01:21
Now same goes for the cast iron.
01:31
So k for the cast iron means that is the stiffness for the cast iron flange equal to 2 pi d square e divided by t equal to 2 into pi multiplied by d the whole means 20 the whole square multiplied by 100 that we have assumed earlier divided by 20.
01:52
So this 20 is our assumed one.
01:56
Now k1 equal to k2 is equal to after solving this we get 212566 .37 kilo newton per mm and here we have 2 cast iron...