00:01
Now, in this problem we are given that a cannon is fired at an angle 30 degrees with the horizontal and if the initial velocity of the cannon ball is 779 feet per second then we need to tell that how far horizontally will the shot travel.
00:24
So this is a cannon ball which is fired at an angle of 30 degrees with the horizontal.
00:30
Now when it is fired it will follow a parabolic path something like that.
00:37
First it will reach at the topmost point and then it will come back to the ground following a parabolic path like this and it again hits on the ground.
00:50
Now we have to find this horizontal distance travelled by the ball.
00:57
This distance d we have to find and also we have to neglect air resistance.
01:03
So if we know the horizontal component of this velocity which is v not cosine theta v not is the initial velocity multiplied with the time of flight.
01:17
So horizontal component we can easily calculate this will be the horizontal component v not cosine theta and the vertical component will be this.
01:27
This is v not sine theta but we don't have the value of t this time of flight.
01:34
So first we are going to find the time of flight.
01:37
Time of flight basically means the time the ball took to move from this position to this final position.
01:44
This is the time that it took will be time of flight.
01:49
So if we know the time of flight we can easily calculate the horizontal distance travelled by the ball.
01:54
So let's first calculate the time of flight.
01:57
For that i am going to use this kinematic formula which is y equals to y not plus v not y times t plus one over two a y t square.
02:10
Now here this direction i have taken positive x and this is the positive y.
02:15
Now y is the final position here which is zero because we have taken this to be origin zero comma zero...