Question

4. A cannonball is fired at an angle of 30° above the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 meters high. a. What is the horizontal component of the cannonball's velocity? b. How much time will it take for the cannonball to hit the ground? c. How far will it travel horizontally before it hits the ground?

          4. A cannonball is fired at an angle of 30° above the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 meters high.
a. What is the horizontal component of the cannonball's velocity?
b. How much time will it take for the cannonball to hit the ground?
c. How far will it travel horizontally before it hits the ground?

4. A cannonball is fired at an angle of 30° above the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 meters high.
a. What is the horizontal component of the cannonball's velocity?
b. How much time will it take for the cannonball to hit the ground?
c. How far will it travel horizontally before it hits the ground?

Added by Alan W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Prabhu Ramji

10/13/2022

Step 1

Given that the initial velocity of the cannonball is 800 m/s and the angle of projection is 30 degrees above the horizontal, we can calculate the horizontal component of the velocity using the formula: \[ v_{0x} = v_0 \times \cos(\theta) \] \[ v_{0x} = 800 \times Show more…

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A cannonball is fired at an angle of 30° above the horizontal with an initial velocity of 800 m/s from the top of a cliff 80 meters high. a. What is the horizontal component of the cannonball's velocity? b. How much time will it take for the cannonball to hit the ground? c. How far will it travel horizontally before it hits the ground?