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Hi there.
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So for this problem, we have a capacitor that is connected to an ac source.
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If the maximum current in the circuit is given and that maximum current is equal to 0 .52 amperts.
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Then, and the voltage from the ac source is also given and that voltage is equal to an amplitude of 80 .8 volts.
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Times the sign of 98 times pi, this times the time.
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So we need to determine the following.
00:47
So for par a, we are asked to calculate the rma's voltage.
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So as you can recognize in here, this corresponds to the maximum voltage that we can have.
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80 .8 volts.
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Now, to calculate the rms value, we just need to divide that maximum value by the square root of 2.
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So that will be 80 .8 volts divided by the square root of 2.
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So from this, we obtain a value of 57 .13 volts.
01:28
So that's a solution for part a of this problem.
01:32
Now for par b, we are asked about the frequency in hearse of the source.
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Now, remember that what multiplies the time in here is the angular frequency.
01:49
And the angular frequency is related to the frequency by just multiplying that by two times pi.
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So the value that we have in here, 98 pi is equal to 2 times pi.
02:02
So you can see in here that we can cancel this pie with this pie.
02:06
So the frequency in this case is just simply divided 98 hertz by 2.
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So that will be 98 divided by 2.
02:18
That will give us the value of 49 hertz...