A car comes to a skidding stop in 15 m. The force on the car due to the road is 1000 N. The work done by road on the car and car on the road, respectively, is
Added by Himi R.
Step 1
Given force on the car, F = 1000 N Displacement, s = 15 m Work done on the car = Force x Displacement Work done on the car = 1000 N x 15 m Work done on the car = 15000 J Show more…
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A car comes to a skidding stop in $15 \mathrm{~m}$. The force on the car due to the road is $1000 \mathrm{~N}$. The work done by road on the car and car on the road, respectively, is (A) $-15 \mathrm{~kJ}$, zero (B) zero, $15 \mathrm{~kJ}$ (C) $15 \mathrm{~kJ}$, zero (D) $-15 \mathrm{~kJ}, 15 \mathrm{~kJ}$
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