00:01
Okay, so this is a video regarding two questions that was posted so i'll solve them one by one these two are not related but individually i'll solve it in the first question we have that a car is initially parked in 0 .5 km north so we have to make the directions so here this is suppose north and this is east this is south okay this is north this is east so the car is parked at 0 .5 kilometers from the origin suppose this is the origin so it is originally at this place so name this as a now this car moves three blocks means 0 .6 kilometers to the east so this distance is 0 .6 kilometers east then it moves two blocks south this is south, so we will be moving in this direction for 0 .4 km.
01:23
This is 0 .4 km south.
01:27
Remember this distance is 0 .5, so it will be slightly lesser than that.
01:31
This is 0 .4 km.
01:33
Then 1 block west.
01:37
So 1 block west will be here.
01:48
1 block means 2 kilometers.
01:52
So it will be, this was being.
01:55
Point five so this is point four so one block point two kilometers in this side then finally one block in the north okay point one kilometer in this side this is the final position b so this was the whole journey now we'll see this questions from this first is the total distance traveled by the car for the short trip so we know that it starts from a so far distance was 0 .6 then 0 .4, then 0 .2, then 0 .1.
02:37
So this is the total distance table.
02:40
6, 4, 10, 12, 13.
02:43
So this will be 1 .3 kilometers.
02:47
This is the total distance travel for the car.
02:50
Second part is the displacement of the car in the form of components.
03:00
So we need to find the final position of the car.
03:03
So final position we can calculate first we'll see the x component so this is 0 this whole length is 0 .5 this is 0 .4 so this will be 0 .1 okay this is 0 .1 this is 0 .1 so the x component will be 0 .2 i plus final position here so in the j direction this is the so this is the j direction so this is the direction okay so in the i direction we have this point six and this will be subtracted from it so point four so that will be point four i this is the x component this is the y component of the this is the final position b okay now subtracting this from the initial position initial position the x component was zero so 0i minus or this will be plus .5 j.
04:23
So this is the point of a and the difference of them will give you displacement.
04:32
So this will be 0 .4i and minus 0 .3j.
04:44
This will be 0 .2, this will be 0 .5 minus 0 .3j.
04:51
So this is the components.
04:59
This is the first answer.
05:02
This is half of the second answer.
05:04
Then again we will see in the component of the second, in the magnitude and direction form.
05:12
So we have to calculate the magnitude of this.
05:15
So the magnitude will be, like suppose we are taking it d, so that d will be under root, i component plus j component.
05:27
So it will be 0 .5.
05:35
Don't confuse it with anything else.
05:37
We are trying to find this line.
05:43
We are trying to measure this distance.
05:45
So this comes out to be 0 .5 kilometers.
05:51
So along with this we need direction also.
05:54
So direction will be along east.
06:00
So we'll calculate it like this.
06:04
So we know the tangent.
06:07
The angle so the 10 theta will be here y component by x component so y component is how much 0 .3 correct and x component is 0 .4 so this is 0 .75 and theta will be equal to so we are taking 10 inverse this comes out to be this is negative so this comes out to be 36 .87 degree okay so how we'll draw this? this is the east and this is the displacement.
06:57
So if we are taking, we have to extend it beyond this and this angle comes out to be 36 .87 degree.
07:06
So this is the whole answer...