00:01
What's the probability that 90 cars pass inspection of a random sample of 100 cars is taken at this inspection office? and it's 88 % likely to pass inspection.
00:12
So we want to find, we want to use our binomial probability distribution.
00:18
The probability is equal to the sum when gamma is equal to r to n of nr times p to the gamma times 1 minus p, to the n minus gamma.
00:33
So what are our values here? n is 100, r is 90, and gamma is what's going to change.
00:42
So our probability that that x is greater than or equal to 90 is going to give us the sum from 90 to 100 of 190 times 0 .88 gamma times 1 minus 0 .88 100 minus gamma.
01:01
So now let's do some values that are, we want to find our value 90 and greater.
01:09
So we will plug in 190 times 0 .88 to the 90 power times 1 minus 0 .88 to the 10 power.
01:20
That's equal to 0 .1033.
01:24
Now we want to do this again.
01:26
We plug in 1091 times 0 .88 times 91 times 1 minus 0 .88 .8...