Since the car starts from rest, $v_0 = 0$. We are given that $d = 96\,\text{m}$ and $t = 8\,\text{s}$. We can now solve for the acceleration $a$:
$$
96 = 0 + \frac{1}{2}a(8^2)
$$
$$
a = \frac{96}{32} = 3\,\text{m/s}^2
$$
a. The acceleration of the car is
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