Question

A car starts from a stop sign and moves along a straight road so its position as a function of time is presented by the following formula $x(t) = at^2 - \beta t^3$, where $a = 1.8 \text{ m/s}^2$ and $\beta = 0.08 \text{ m/s}^3$. Calculate the average velocity of the car from $t = 0$ to $t = 5$ s. Calculate the instantaneous velocity of the car at $t = 0$, $t = 5$ s, $t = 10$ s. Calculate the time it takes for the car to be again at rest. How far from the starting point will the car be at rest? ***Pleas show the steps to convert on 1.8m/s2 and 0.08m/s

          A car starts from a stop sign and moves along a straight road so its position as a function of time is presented by the following formula $x(t) = at^2 - \beta t^3$, where $a = 1.8 \text{ m/s}^2$ and $\beta = 0.08 \text{ m/s}^3$.
Calculate the average velocity of the car from $t = 0$ to $t = 5$ s.
Calculate the instantaneous velocity of the car at $t = 0$, $t = 5$ s, $t = 10$ s.
Calculate the time it takes for the car to be again at rest. How far from the starting point will the car be at rest?
***Pleas show the steps to convert on 1.8m/s2 and 0.08m/s

A car starts from a stop sign and moves along a straight road so its position as a function of time is presented by the following formula x(t) = at^2 - β t^3, where a = 1.8 m/s^2 and β = 0.08 m/s^3.
Calculate the average velocity of the car from t = 0 to t = 5 s.
Calculate the instantaneous velocity of the car at t = 0, t = 5 s, t = 10 s.
Calculate the time it takes for the car to be again at rest. How far from the starting point will the car be at rest?
***Pleas show the steps to convert on 1.8m/s2 and 0.08m/s

Added by Amber M.

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