A car starts from rest and moves with a constant...

A car starts from rest and moves with a constant acceleration of 1 .5 m/s2 until it achieves a velocity of 25 m/s. It then travels with constant velocity for 60 seconds. Determine the average speed and the total distance traveled.

Transcript

00:01 Hello everyone.

00:02 It is given the question that a car start from race, so its initial velocity is 0 meter per second and moves with the constant acceleration of 1 .5 meter per second square until it reaches a speed of 25 meter per second.

00:16 Okay, so when it reaches 25 meter per second, then after that it moves with the constant velocity that the velocity, this is the velocity that he attained.

00:27 So it moves with the same velocity after that for 60 seconds.

00:31 Then we need to find out the average speed and the total distance table by the car.

00:35 So for that we can apply a concept here that is by applying first equation of motion.

00:44 So from first equation of motion we can write v is equal to u plus a t.

01:01 Why we are applying this equation of motion because for average speed we need to find out the total time taken and the total distance so we can find the time from this question is 25 the final velocity is going 25 initial is 0 the acceleration given is 1 .5 multiplied by time this is the time taken by the car during its uniformly accelerated motion okay so this time will return as 25 divided by 1 .5 and it come out to be 16 .67 seconds okay so this is the time taken by a car to attain a velocity of 25 meter per second okay then we can apply again the second concept that is from third equation of motion we can find the distance traveled by the car during its uniformly accelerated motion so third equation of motion v square minus u s square is equal to two so from this the final series is 25 square initial is 0 square is equal to 2 multiplied by 1 .5 multiplied by distance so from this 625 3 s so this is equal to 625 divided by 3 s so this is equal to 625 divided by 3 from these 208 point 3 3 3 3 3 so this is the distance traveled by car during its uniformly accelerated motion.

03:13 So we find the time taken by the car during its uniformly accelerated motion and we find the distance traveled by the car during its uniformly accelerated motion.

03:22 Right...

Question

A car starts from rest and moves with a constant acceleration of 1 .5 m/s2 until it achieves a velocity of 25 m/s. It then travels with constant velocity for 60 seconds. Determine the average speed and the total distance traveled.

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