Question

A car travels 14.3 m in 10.9 seconds at a constant speed. It then accelerates over a period of 53.1 s, reaching a final speed of 28.6 m/s. What was the car's average acceleration over those 53.1 seconds? $a = \_\_\_\_\_\_\_\_\_\_ m/s^2$

Name: a car travels 143 m in 109 seconds at a constant speed it then accelerates over a period of 531 s reaching a final speed of 286 ms what was the cars average acceleration over those 531 secon 39682
Uploaded: 2023-04-01T22:04:39-08:00
Duration: 1 min 25 s
Channel: Timothy James
Description: a car travels 143 m in 109 seconds at a constant speed it then accelerates over a period of 531 s reaching a final speed of 286 ms what was the cars average acceleration over those 531 secon 39682

          A car travels 14.3 m in 10.9 seconds at a constant speed. It then accelerates over a period of 53.1 s, reaching a final speed of 28.6 m/s. What was the car's average acceleration over those 53.1 seconds?
$a = \_\_\_\_\_\_\_\_\_\_ m/s^2$

a car travels 143 m in 109 seconds at a constant speed it then accelerates over a period of 531 s reaching a final speed of 286 ms what was the cars average acceleration over those 531 secon 39682

Added by Jesse N.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Timothy James

04/01/2023

Step 1

The car travels 14.3 m in 10.9 seconds at a constant speed. The formula for constant speed is: $v = \frac{d}{t}$ where $v$ is speed, $d$ is distance, and $t$ is time. Given: Distance $d = 14.3$ m Time $t = 10.9$ s Calculate the initial speed ($v_i$): $v_i = Show more…

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A car travels 14.3 m in 10.9 seconds at a constant speed. It then accelerates over a period of 53.1 s, reaching a final speed of 28.6 m/s. What was the car's average acceleration over those 53.1 seconds? $a = \_\_\_\_\_\_\_\_\_\_ m/s^2$