A car travels along a straight line with a velocity given by v = (12 + 12t - 6t^2) m/s. When t =

Question

Satish Yadav · Answer

Given the displacement s is equal to 4 .5 t squared and t is in the interval 0 to 12 we have to

Adi S · Answer

the position vector is given as here s is equal to 4 .5 t square okay and here the range of t is

Zhumagali Shomanov · Answer

In this question, we are given a car&#x27;s position and we are asked to find its average velocity fo

Carson Merrill · Answer

So first we want to start off by graphing this model that we have. It&#x27;s s equals 4 .5 t squared.

Satpal Satpal · Answer

Let us first draw the velocity time diagram for the given velocity equation. This is y -axis den