00:01
Hi, in the given question we have a car moving due east which is along the positive x direction with velocity 34 km per hour that is denoted as vc which is equal to 34 kilometer per hour and rain is falling vertically to earth with velocity we are so let this be the velocity of rain which is falling vertically downward.
00:36
This is a negative y direction.
00:40
And we are asked to find the velocity of rain with respect to earth as well as with respect to car.
00:48
So let us see how we can solve this problem.
00:50
Let we see with the velocity of car and we are the velocity of rain.
01:02
Then we can find velocity of rain with respect to car which is equal to velocity of rain minus velocity of car these are all vector quantities or we can write this as velocity of rain plus negative of velocity of so we need to subtract velocity of car from rain so vectorially or in the figure we can change the direction of velocity of car but the magnitude remains the same so this is the velocity of car in the opposite direction minus v z and now we have to find the resultant so draw a parallelogram and the resultant will be the velocity of rain with respect to car so in the question we have velocity of car is equal to 44 km per hour in the east.
02:09
So it is in the positive direction so i'm denoting it by a gap.
02:14
And velocity of rain let it be v which is in the negative y direction so minus v .j gap.
02:26
And we are asked to find velocity of rain with respect to car as well as this velocity of rain.
02:33
And in the question we are given that the rain rain is a little rain.
02:37
Falling at an angle of theta where theta is equal to 50 degree.
02:45
So making the figure more clear we can draw...