We'll use SI units (Joules and Kelvin).
* Work done (W) = 440 kW = 440,000 J/s
* Heat input ($Q_H$) = 680 kcal/s. Since 1 kcal = 4184 J, $Q_H$ = 680 kcal/s * 4184 J/kcal = 2844320 J/s
* Temperature of heat source ($T_H$) = 570°C = 570 + 273.15 K = 843.15 K
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