Question

A Carnot engine working between 377°C and 37°C produces 120 kJ of work. Determine (i) The heat added in kJ, (ii) The entropy change during the heat rejection process, (iii) The engine thermal efficiency. [Ans: (i) 229.5 kJ, (ii) 0.353 kJ/K, (iii) 52.37%]

Name: a carnot engine working between 377c and 37 produces 120 kj of work determine i the heat added in kj ii the entropy change during heat rejection process iii the engine thermal efficiency ans 17157
Uploaded: 2022-06-08T06:08:52-08:00
Duration: 53 s
Channel: Sri K
Description: a carnot engine working between 377c and 37 produces 120 kj of work determine i the heat added in kj ii the entropy change during heat rejection process iii the engine thermal efficiency ans 17157

          A Carnot engine working between 377°C and 37°C produces 120 kJ of work. Determine (i) The heat added in kJ, (ii) The entropy change during the heat rejection process, (iii) The engine thermal efficiency. [Ans: (i) 229.5 kJ, (ii) 0.353 kJ/K, (iii) 52.37%]

Added by Erik M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Sri K

06/08/2022

Step 1

However, the temperatures need to be in Kelvin for this formula. So, first convert the temperatures from Celsius to Kelvin. T1 = 377°C + 273 = 650 K T2 = 37°C + 273 = 310 K Now, substitute the values into the formula: Q1 = 120 kJ / (1 - 310/650) = 229.5 kJ (ii) Show more…

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A Carnot engine working between 377°C and 37°C produces 120 kJ of work. Determine (i) The heat added in kJ, (ii) The entropy change during the heat rejection process, (iii) The engine thermal efficiency. [Ans: (i) 229.5 kJ, (ii) 0.353 kJ/K, (iii) 52.37%]