00:01
Hello students, in this question given as a carnot engine and the carnot engine of high temperature value is given as 200 degrees celsius which is equals to the 473 kelvin and the lower temperature value is given as 20 degrees celsius which is equals to 293 kelvin and the output that means work done is given as 15 kilowatt.
00:31
Now in the first part of the question we have to calculate the we have to calculate the received heat from the high temperature and the transfer heat to the low temperature.
00:43
So for this first of all we will write the efficiency.
00:46
Efficiency we know that 1 minus t2 by t1 so this will be equal to the 0 .38.
01:03
Now we know that the efficiency is equals to output upon input so output is work done and input is heat taken heat from the high temperature that is q1.
01:19
So now q1 will be equal to the output the output is given as the 15 kilowatt upon upon 0 .38.
01:38
So after calculation we will get the q1 will be equal to the 39 .42 kilowatt.
01:49
This is the heat this is the heat received from the high temperature and next q2 upon q1 is equals to we know that t2 upon t1.
02:04
Now the q2 will be equal to the now we will substitute all the values 293 upon 473 into q1.
02:16
Q1 which we have calculated 39 point so after calculation we will get the q2 is equals to 24 .42 kilowatt...