A Carnot heat engine receives heat at $900 \mathrm{K}$ and rejects the waste heat to the environment at $300 \mathrm{K}$. The entire work output of the heat engine is used to drive a Carnot refrigerator that removes heat from the cooled space at $-15^{\circ} \mathrm{C}$ at a rate of $250 \mathrm{kJ} / \mathrm{min}$ and rejects it to the same environment at 300 K. Determine ( $a$ ) the rate of heat supplied to the heat engine and $(b)$ the total rate of heat rejection to the environment.
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Step 1
143 = \frac{300}{900 - 300} \] \[ \text{Heat supplied to the heat engine} = \frac{250}{6.143} = 40.7 \text{ kJ/min} \] Show more…
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