0:00
Hi there.
00:02
So for this problem, we have a carbonate heat engine that uses a hot reservoir consisting of a large amount of boiling water and a cool reservoir consisting of a large tube of ice and water.
00:17
Now, in nine minutes of alteration, the heat rejected by the engine melts a mass that is given and that mass is equal to 0 .0, 445 kilograms of ice.
00:39
During this time, how much work is performed by the engine? in this case, we're going to call the temperature of the fur reservoir where we have boiling water, and we know that the temperature of boiling water is 100 celsius degrees, which is the same as 373 kelvin and the temperature for the cold reservoir where we have ice and water it should be to 0 celsius degrees which is the same as 273 kelvin.
01:22
Now the heat rejected is used to melt ice.
01:28
So with that said that heat is just simply the product between the mass of the ice that is 0 .0 ,400, and 45 kilograms.
01:44
This times the latin heat of fusion.
01:48
So that latin heat is 334 times 1 ,000.
01:54
So the value that we obtained from this is equal to 14 ,863.
02:11
Jules.
02:14
Now we use, so this is the heat c which is the heat rejected.
02:23
Now the temperature of the hot reservoir divided by the temperature of the cold reservoir should be equal to the heat that we want to determine...