00:01
Hello in the question it is given consider one carrier wave with the ec that is equal to 10 sine 6 .28 into the power 60 and this is used to transmit the audio signal that is em is equal to 5 sine 6 .28 into the power 3 t and we need to find the central frequency of carrier wave that is a new c that we need to find out.
00:37
So comparing this equation with the general equation, that is a sine omega -t.
00:43
So here, omega is equal to we know that 2 pi new.
00:47
So since it is carrier wave frequency should be carrier frequency.
00:52
So in this place, in the place of omega, we have 6 .28 into 10 to the power 6.
00:59
So, omega must be equal to 6 .28 into 10 to power 6.
01:04
And comparing these two equations, in lhside it is equal.
01:10
So we can equate rhside that is 2 pi, nu c is equal to 6 .28 into 10 to power 6.
01:17
So here, 2 into 5, that is 3 .14 into new c is equal to 6 .28 into 10 to power 6.
01:27
So 2 into 3 .14 is nothing but 6 .28 into nuc.
01:33
So this is equal to 6 .28 into 10 to the power 6...