00:01
Hello students, in this question we have the bincladge of the dimensions that is it have dimensions 20 x 80, 40 x 160 and depth of 260 with 20 millimeter wide web and having a compressible which is equal to 20 newton per meter cube.
00:28
First we have look at the y beam.
00:30
So y bottom which is equal to 160 x 40 x 20 plus 260 x 20 x 40 plus 130 plus 20 x 80 x 40 plus 260 plus 10 all divided by denominator is 160 x 40 plus 260 x 20 plus 20 x 80.
01:07
So if we look at the figure we can say that y b we can write this is 160 millimeter 20 millimeter and here is also 20 web and total depth is 260.
01:19
So we can find y bottom which is equal to 114 .24 millimeter.
01:30
Now we have area to find area we can write sigma a is equal to multiplying and adding all dimensions.
01:38
So 160 x 40 plus 260 x 20 plus 20 x 80.
01:46
So we have which is equal to 13200 millimeter square.
01:52
Now we are looking at the y b.
01:57
So we can write y top to find y top we have using the equation that is y top is equal to 20 plus 260 plus 40 minus y bottom.
02:15
So we have 320 minus y b we have y b is 114 .24.
02:21
So we have y top is equal to 205 .76 millimeter.
02:27
Now we are looking at the i base base of moment inertia of base.
02:32
So we can write i is equal to 160 x 40 cube divided by 3 plus we have 20 x 260 cube divided by 12 plus 20 x 260 x 110 square and all divided by we have 80 x 20 cube divided by 12 plus 80 x 20 x 250 square.
03:10
So we have i is equal to 234 .6 x 10 raise to 6 millimeter raise to 4.
03:19
So now the using the equation for the bending we have m by a is equal to f t by y b which is equal to f c by y t.
03:31
So we can write now the maximum tensile strength we have equation to find y t is equal to that is f c is equal to f t into y c by y b...