00:01
In this problem, we're going to be dealing with the erroneous equation.
00:06
This is the arrenous equation, and we're told catalyst is lowering the activation energy from 215 kilojoules to 206 kilojoules.
00:21
We want to know how that affects the value of k.
00:27
So when we lower the activation energy, the value of k is going to go up, because the speed of the reaction goes up so it would make sense because rate is equal to k times concentration of reactants from the uranus equation we should be able to determine the factor by which k is going to be increasing we're told that a is the same for both reactions and the temperature is 25 degrees celsius which we can convert to kelvin so let's set the new k after the activation energy is lowered to k and we are just going to set that equal to the rest of the uranus equation.
01:26
And then we're going to do the same for k1, so that's before the activation energy was lowered.
01:38
And we're told that the a's are the same.
01:41
These will therefore cancel out.
01:43
So we're going to get this proportion.
01:57
So if we plug in the numbers on the right, we can determine what k2 divide by k1 is going to be.
02:10
So let's plug in the numbers...