00:01
So, here in this question we are considering about a casual system which is represented by the following differential equation that is y of n plus 0 .25 of y of n minus 1 is equals to x of n plus 0 .5 of x of n minus 1.
00:16
So, this is the equation we are given here.
00:18
In the first part, we have to find out the system function of hg giving the corresponding result of the correspond.
00:24
So, here we can apply the z transform here.
00:29
So, that from here is equals to y of z plus 0 .25 of z inverse y of z is equals to x of z plus 0 .5 of z inverse which is multiplied by the x of z bar.
00:44
So, the value of y of z multiplied by the 1 plus 0 .25 of z inverse become equals to x of z which is multiplied by the 1 plus 0 .5 of z inverse.
00:55
So, we can say that h of g become equals to y of z which is divided by x of z that become equals to 1 plus 0 .5 of z inverse that is divided by 1 plus 0 .25 of z inverse.
01:09
So, the value of hg from here is equals to z plus 0 .5 which is divided by z plus 0 .25.
01:17
This is the value of the hg from here and we are considering about we have to find the reason of the convergence.
01:23
So, let's say we are considering z from here is greater than 0 .25 is the reason of convergence.
01:29
So, this is the answer to the part a of the question.
01:31
Now, we are considering about the part b where we are considering about the unit step response.
01:37
So, unit step response is what we are considering here.
01:40
So, here we can say that x of z is equals to z which is divided by z minus 1...