A certain disease has an incidence rate of 0.8%. If the false negative rate is 4% and the false positive rate is 4%, compute the probability that a person who tests positive actually has the disease. Give your answer accurate to at least 3 decimal places
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Let P be the event that a person tests positive. We are given that the incidence rate of the disease is 0.8%, so $P(D) = 0.008$. The false negative rate is 4%, which means that the probability of testing negative given that the person has the disease is $P(P^c|D) Show more…
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