A certain gas whose R = 278.6 J/kg-K and cp = 1.015 kJ/kg-K expands isentropically from 1517kPa, 288°C to 965 kPa. Determine the work nonflow -21.9 kJ/s -30.18 kJ/s 21.9 kJ/s 30.18 kJ/s
Added by Michael J.
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To do this, we can use the equation: T2/T1 = (P2/P1)^((gamma-1)/gamma) where T1 and T2 are the initial and final temperatures, P1 and P2 are the initial and final pressures, and gamma is the specific heat ratio. Given: P1 = 1517 kPa T1 = 288.9 °C = 288.9 + Show more…
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