00:01
For this problem, we have a current running through an inductor.
00:04
That current is changing at a rate of 0 .064 amps per second.
00:09
And the induced emf associated with this is 0 .116 volts.
00:15
Our goal is to find the self -inductance, l.
00:18
So let's see two different ways to do this.
00:22
So we could first just recall, the quickest way is to just recall that the emf is equal to the self -inductance multiplied by this rate of change of the current, then rearrange to isolate our self -inductance.
00:42
When both of these were given, so the emf is 0 .016 volts, and the change in current, the rate is 0 .064 amps per second.
00:57
This is just a quarter, so we have 0 .25 henries.
01:01
The other way is to recall that the self -inductance is defined as the flux divided by the current responsible for establishing it...