A certain reaction has an activation energy of 49.9 kJ/mol. If the rate constant is 1.40 x 10-3 M-1s-1 at 276 K, to what temperature (in K) must the reaction be raised in order to double the rate of the reaction?
Added by Terri S.
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We are given the activation energy (Ea) as 49.9 kJ/mol, the rate constant (k1) as 1.40 x 10^-3 M^-1s^-1, and the initial temperature (T1) as 276 K. We want to find the temperature (T2) at which the rate constant (k2) is doubled. Show more…
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