Question

A certain tennis player makes a successful first serve 77% of the time. Assume that each serve is independent of the others. If she serves 4 times, what's the probability she gets a) all 4 serves in? b) exactly 2 serves in? c) at least 2 serves in? d) no more than 3 serves in?

          A certain tennis player makes a successful first serve 77% of
the time. Assume that each serve is independent of the others. If
she serves 4 times, what's the probability she gets a) all 4
serves in? b) exactly 2 serves in? c) at least 2 serves in? d)
no more than 3 serves in?
        
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Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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A certain tennis player makes a successful first serve 77% of the time. Assume that each serve is independent of the others. If she serves 4 times, what's the probability she gets a) all 4 serves in? b) exactly 2 serves in? c) at least 2 serves in? d) no more than 3 serves in?
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A certain tennis player makes a successful first serve 73% of the time. Assume that each serve is independent of the others. If she serves 8 times, what's the probability she gets a) all 8 serves in? b) exactly 3 serves in? c) at least 6 serves in? d) no more than 5 serves in?

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A certain tennis player makes a successful first serve 73% of the time. Assume that each serve is independent of the others. If she serves 7 times, determine the following probabilities. a) All 7 first serves will be in. b) Exactly 4 serves will be in. c) At least 5 serves will be in.

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Transcript

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00:01 A tennis player makes a successful serve 77 % of the time.
00:05 And we're looking at four independent serves.
00:08 So n is 4.
00:09 And p probability that she makes a successful first serve is 0 .77%.
00:16 So because we have four independent trials, two outcomes, successful or not, same probability on each serve, we have a binomial distribution.
00:27 So we can use the binomial formula for this question, and i'll need to do that.
00:34 The binomial formula is the probability of exactly x successes, is n choose x, p to the x, 1 minus p to the n minus x.
00:45 We don't really need it for part a, because part a is the same thing happening four times in a row.
00:51 Because these are independent, we can combine their probabilities by multiplication.
00:56 So it's the probability of success multiplied by itself for the four attempts.
01:04 0 .77 to the power of 4, 0 .3515.
01:12 So you could use the formula, but the first term would just be a 1, the last term will just be a 1 as well.
01:19 Next for part b, exactly two serves.
01:25 So two successes, two failures.
01:29 This term is for the 2, 3.
01:31 Successes.
01:35 Not .77 multiplied by itself.
01:38 This term is for the two failures.
01:41 The rest of the time, the other 23 % of the time, again twice.
01:47 This is the probability.
01:48 The first two serves are successful, the last two are not.
01:52 That's two out of four, but it's not the only way that might happen.
01:56 Maybe the first one is successful, then there are two failures, then a success.
02:00 That also has this probability, but fundamentally it's a different outcome.
02:06 We need to account for every possible order that these could come in.
02:10 This term tells us how many orders there are...
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