A chair of mass 8.5 kg is sitting on the horizontal floor; the floor is not frictionless. You push on the chair with a constant force 15.5 N that is directed at an angle of 35.0 degree below the horizontal and the chair slides on the floor with 0.46 m/s2 acceleration. How big is the normal force (in Newtons) acted on the chair?
Added by Jessica H.
Step 1
\( F_{\text{vertical}} = F \times \sin(35^\circ) \) \( F_{\text{vertical}} = 15.5 \, \text{N} \times \sin(35^\circ) \) \( F_{\text{vertical}} = 15.5 \, \text{N} \times 0.574 \) Show more…
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