A chemical reaction takes place in a container fitted with a piston of cross-sectional area 50.0cm^3. As a result, the piston is pushed out through 15cm against an external pressure of 1.0atm. Calculate the work done by the system
Added by Sergio G.
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The area is given as 50.0 cm². 1 cm² = 0.0001 m², so: \[ 50.0 \, \text{cm}^2 = 50.0 \times 0.0001 \, \text{m}^2 = 0.0050 \, \text{m}^2 \] Show more…
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