00:01
Hello students, so for this reaction the mass of a sample of c4h8o is given as 490 mg.
00:11
That is, let us convert this to grams, so divide by 1000, that is 0 .491 g.
00:18
The initial temperature is minus 5 .3 degrees celsius and the final temperature is 7 .8 degrees celsius.
00:24
So, the change in temperature will be t2 minus t1, that is 7 .8 minus of minus 5 .3 degrees celsius, that is equal to 13 .1 degrees celsius.
00:39
The heat required for this temperature rise is 10 .8 j.
00:43
So, we have to find the molar heat capacity.
00:46
So let the molar heat capacity of c4h8o be cm.
00:57
So, we know that q is equal to mc delta t, where c is the heat capacity or for the matter of fact specific heat capacity.
01:11
So, we can say that c is equal to q by m delta t, that is equal to 10 .8 by 0 .491 into 13 .1...