00:01
In stoichiometry, we relate the quantities of the substances that are involved in a chemical reaction.
00:07
Here we have the balanced chemical equation for the reaction between agno3 and nacl to form sodium nitrate and silver chloride.
00:21
It is given that 4 .1 grams of agno3 react with 3 .5 grams of nacl and the reaction produces 4 .8 grams of agcl.
00:35
You want to find the percent yield.
00:37
So for the balanced chemical equation, we find that for every one mole of agno3, one mole of nacl reacts and one mole of agcl forms.
00:47
Let's find the moles of the reactant or the mass of the product agcl formed from each of the given mass of the reactant.
01:06
So first, from 4 .1 grams of agno2.
01:12
So we'll apply the measure analysis approach here, starting with 4 .1 grams of agno3.
01:19
We'll divide this by the molar mass of agno3, which is equal to 169 .9 to bring this into moles of agno3.
01:39
And then, using the relationship that one mole of agno3 will form one mole of agcl, we'll be able to find the moles of agcl.
01:50
And ultimately, find the mass of agcl by multiplying by the molar mass, which is 143 .3.
01:58
So as we can see, the units here cancel.
02:01
So we bring the grams of agcl as needed.
02:06
We solve for this and we get 3 .46 grams...