A chemist measures the enthalpy change ΔH during the following reaction:
8 SO2(g) + 16 H2S(g) → 3 S8(s) + 16 H2O(l) ΔH = -1863 kJ
Use this information to complete the table below. Round each of your answers to the nearest kJ/mol.
reaction | ΔH
16SO2(g) + 32H2S(g) → 6S8(s) + 32H2O(l) | kJ
3S8(s) + 16H2O(l) → 8SO2(g) + 16H2S(g) | kJ
3/4 S8(s) + 4H2O(l) → 2SO2(g) + 4H2S(g) | kJ