00:02
Hi there, what we have here is a dilution problem because we are starting with a stock solution of a certain concentration and we want to dilute that or make it less concentrated.
00:15
And for a dilution problem the equation that we want to use is m1 times v1 equals m2 times v2.
00:26
Where m is molarity, v is volume, the 1's represent the stock solution and the 2's represent the diluted solution.
00:33
This equation works because molarity times volume gives us moles.
00:38
So the number of moles that we take out of the stock solution are going to be the same number of moles that are still in the diluted solution.
00:45
It's just that we have more volume in the diluted solution so it's less concentrated.
00:50
Okay, using this equation we can solve for our answer.
00:54
We know that our stock solution has a concentration of 1 .88 moles per liter.
01:00
In other words, that's its molarity because molarity is moles per liter.
01:07
And we want to know what volume of the solution we need to use so that we can create a solution that has a molarity of 1 .00 and we need 475 milliliters of that.
01:25
Okay, so we have an algebra problem here essentially now where we just need to solve for v1...