A chemist must prepare \( 300 . \mathrm{mL} \) of \( 48.0 \mu \mathrm{M} \) aqueous zinc oxalate \( \left(\mathrm{ZnC}_{2} \mathrm{O}_{4}\right) \) working solution. He'll do this by pouring out some \( 0.0000734 \frac{\mathrm{~mol}}{\mathrm{~L}} \) aqueous zinc oxalate stock solution into a graduated cylinder and diluting it with distilled water. Calculate the volume in mL of the zinc oxalate stock solution that the chemist should pour out. Be sure your answer has the correct number of significant digits. \( \square \) mL \( \square \) 10
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0 \, \mu \text{M} = 48.0 \times 10^{-6} \, \text{mol/L}\) - Volume of working solution: \(300 \, \text{mL} = 0.300 \, \text{L}\) - Concentration of stock solution: \(0.0000734 \, \text{mol/L}\) Show more…
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