0:00
Hey, hello everyone.
00:01
This particular question is very simple and very interesting and very basic question.
00:07
Okay, so in this particular reaction what we are going to find and that is what? the molarity of the br minus.
00:14
Okay.
00:15
So from the question we can conclude that the reaction is simply m .gbr2 which is magnesium bromide which is giving us m .g 2 plus plus 2br minus.
00:32
Very simple and here we can see that one m g br 2 is decomposing into 2 moles of br minus from the reaction we can say this one right so first thing first we have to calculate the moles of the m g brr 2 and the number of moles of m gbr 2 is going to be what given bands by molar mass and the given mass of the m g br 2 is given in the question that is 0 .60 right divided by 1 184 .1 is the molar mass of the mgbr2.
01:07
Just calculate this one.
01:08
And after that you are getting the moles of the mgbr2 as how much? that is 0 .0032 moles of mgbr2, right? right? right? this is very simple.
01:24
After that, we are going to calculate the molarity.
01:28
Molarity of what? molarity of moldarity of m...