A chi-square test of independence is calculated from data in a 4 × 5 table with a test statistic of χ2 = 6.15. Assuming a .05 level of significance, identify the critical value and state your conclusion about the null hypothesis. Critical value @ .05 State your conclusion.
Added by Victor Manuel G.
Step 1
05. Given that the table is 4x5, we have degrees of freedom as (4-1)(5-1) = 3x4 = 12. Look up the critical value for chi-square with 12 degrees of freedom and a significance level of 0.05. The critical value is 21.026. ** Show more…
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