00:01
In this problem, we have been given that there are two blocks which are released from rest, and one of the block is lying on the inclined surface, where the coefficient of friction between the surface will be 0 .4.
00:12
And the angle of incline is 40 degrees, so we need to determine the acceleration of the blocks.
00:18
So drawing the free body diagram of this 2m block, there will be weight, that's 2mg, and there will be tension.
00:25
So let's say the block accelerates with a.
00:30
So here as the objects are connected, the blocks will accelerate at the same rate.
00:36
So writing the net force equals mass times acceleration for both the blocks.
00:41
We see that for 2m block, 2mg minus d, that will be equal to 2m into the acceleration.
00:49
Now that's equation 1.
00:50
Also here we see that the weight acts on this block of mass m and there will be normal force here.
00:58
Also there will be tension.
00:59
And there will be friction force and that friction force will be mu times the normal force.
01:06
And normal force here will be equal to the component of the weight in this direction.
01:12
So that will be mg cos 40 degree...